If an acid is an H+-donor,
then the stronger an acid is, the more effectively it will be able to
donate H+. If that acid is in aqueous solution, we can
think of “strength” by the following equilibrium for the generic
acid, HA(aq):
HA(aq) + H2O(l)
↔ H3O+(aq)
+ A-(aq)
In equilibrium terms, the stronger an
acid is, the more product-favored
the equilibrium will be. Since this equilibrium expression can be
applied to any acid, and acids are an important and diverse class of
compounds, we define this equilibrium as an acid
dissociation
equilibrium and call its corresponding equilibrium constant the acid
dissociation constant,
or Ka.:
Similarly, we can think of the strength
of a base using the equilibrium for the generic base, B(aq):
B(aq) + H2O(l)
↔ OH-(aq) +
BH+(aq)
With its corresponding base
dissociation constant,
Kb:
Looking at the Ka
equilibrium equation, the water that appears on the reactant side is
accepting H+
to become H3O+(aq).
If water is accepting a proton, it is acting as a Bronsted-Lowry
base. Considering the reverse
reaction, H3O+(aq)
is a proton-donor so it is acting as an acid, while A-(aq)
is accepting a proton as B-L base. These acids and bases are not
independent of each other, they are conjugate acid-base
pairs.
A-(aq)
is the conjugate base of HA(aq), and HA(aq) is the conjugate acid of
A-(aq);
H2O(aq)
is the conjugate base of H3O+(aq),
and H3O+(aq)
is the conjugate acid of H2O(aq).
A conjugate acid-base pair are related by the addition or removal of
a single H+.
The same relationships can be described for the Kb
equilibrium expression.
In
the Ka
equilibrium, water is acting as a base, while in the Kb
equilibrium, water is acting as an acid. So what is water, an acid
or a base? The answer is BOTH!
The acid or base behavior of a substance is dependent upon its
environment because acid and base are relative terms. In the case of
water, if the water molecules are interacting with something that is
more acidic than water, then water will act as a base. Likewise, if
the water molecules are interacting with something that is more basic
than water, the water will act as an acid. This brings up an
interesting question: is water an acid or a base when it's not
interacting with any other substance? Consider the following
equilibrium:
H2O(l)
+ H2O(l)
↔
H3O+(aq)
+ OH-(aq)
Once
again, water is acting as both an acid and
a base. This process is called autoionization.
Since water is such an important substance for life on Earth, this
equilibrium also has a specific letter assigned to it, Kw,
the autoionization constant for water:
Like almost all equilibria, Kw
is dependent upon temperature. At 25°C,
Kw = 10-14. For pure water, this means that at
25°C, [H3O+]
= [OH-] = 10-7M. If this equilibrium constant
only applied to pure water, it would be interesting but of limited
use. Fortunately, it can be applied to any relatively dilute aqueous
solution to understand the relative amounts of hydronium and
hydroxide ions present in the solution. Consider an acid, HA(aq),
and its conjugate base, A-(aq), both interacting with
water:
HA(aq) + H2O(l)
↔ H3O+(aq)
+ A-(aq)
A-(aq) + H2O(l)
↔ OH-(aq) +
HA(aq)
If these equilibrium equations are
added together, the result is the Kw equilibrium equation.
When two (or more) sequential equilibria are added together, the
equilibrium constant for the overall process is the product
of the equilibrium constants for the individual steps. This means
that for any conjugate acid – conjugate base pair, Ka
x Kb
= Kw.
This also implies a general relationship, the stronger an acid is,
the weaker its conjugate base, and vice versa.
This
has been a lot of acid and base information wrapped up in a big
discussion of equilibrium. Ka,
Kb,
and Kw
all describe specific systems, but the most important thing to
remember is that at their core, these are all equilibrium constants.
They behave like every other equilibrium constant, they follow all
the same rules as every other equilibrium constant, and they can be
manipulated just like any other equilibrium constant. The only thing
special about them is that they refer to a specific type of chemical
equation.
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