2012/07/05

First in-class problem from 2012-07-05


2.63M NOCl2(g) → NO(g) + Cl2(g) K=0.118, find all [ ]eq

NOCl2(g) ⇄
NO(g) +
Cl2(g)
[ ]initial
2.63 M
0 M
0 M
Δ [ ]
- x M
+ x M
+ x M
[ ]equilibrium
(2.63 – x) M
x M
x M
Plugging in to the equilibrium constant expression...
Because the value of K is not exceptionally large or exceptionally small, this one will probably require working through the quadratic. Breaking it down in steps...
(x)(x) = 0.118(2.63-x)
x2 = 0.31034 – 0.118x
x2 + 0.118x + (-0.31034) = 0
Plugging in to the quadratic formula:
NOTE: The other root is negative, it doesn't work in this problem.
[NOCl2]eq = 2.63 – 0.50 = 2.13M
[NO]eq = x = 0.501M
[Cl2]eq = x = 0.501M


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