2012/04/28
Exams and keys posted
This year's Gen Chem II exams and (some of) the keys are posted at http://www.drbodwin.com/teaching/jbgenchem.html . I'll try to get all the keys posted tomorrow.
2012/04/27
Standardized Final Exam
Your final exam will be a standardized American Chemical Society exam. I know a number of you are a little anxious about this, but there are a few things to remember:
1. "Standardized" does not mean "impossible unless you're a genius". "Standardized" just means that there are national averages to which your score can be compared. This allows your performance to be scaled to Gen Chem students at any other school.
2. If I've done my job, I have helped you learn all the fundamental material in General Chemistry. I certainly hope that I'm giving you as good an education in General Chemistry as you would get at any other university, in fact, I would hope that I'm giving you a better Gen Chem education than you would get at most other universities. By occasionally using a standardized exam, I can see what things I'm doing well and what areas I need to improve to give future Gen Chem students the best possible education.
3. The format and length might vary slightly, but expect 70 questions and a 110 minute time limit. That's almost 2 hours, and 1.5 minutes per question. Some questions will be quicker than others, but at 1.5 minutes per question, none of them can be huge. Many of the questions on my exams are probably 10-20 minute questions by the time you work through all the parts, none of the questions on the ACS exam will be anywhere near that complex.
4. 70 questions means that each question is worth XX% of the total score. {I'll leave the calculation of "XX" for you to do as a practice math problem.} Scaling that to 200pts (the value of your final exam), means that each question would only be worth YYpts if I plugged your scores directly into my grade sheet. {Again, "YY" is a practice math problem...} On my exams, if you totally miss one of the big questions, you lose ~10%, sometimes more. Yikes.
5. It is quite unlikely that I will plug your scores directly into my grade sheet, I will almost certainly be using some sort of scaling formula to calculate a score out of 200 points. That doesn't mean you shouldn't prepare well for the exam, a good score can really help and a poor score can definitely hurt your final score/grade in the class.
6. There are resources available for you to use as practice. The actual ACS Gen Chem exams are not published, BUT every year the ACS prepares exams for the Chemistry Olympiad for high school students. These are not identical to the ACS Gen Chem exam, but the questions are similar and the style/format is almost the same. The ACS posts their old Chemistry Olympiad exams online, so you can look them over to help you prepare. Check out: http://portal.acs.org/portal/acs/corg/content?_nfpb=true&_pageLabel=PP_SUPERARTICLE&node_id=1508&use_sec=false&sec_url_var=region1&__uuid=1c147f5a-ee17-44e2-af0c-87ca446c65a8
for 10+ years of previous Chemistry Olympiad exams from both the local and national level competition.
Good luck in your preparation.
1. "Standardized" does not mean "impossible unless you're a genius". "Standardized" just means that there are national averages to which your score can be compared. This allows your performance to be scaled to Gen Chem students at any other school.
2. If I've done my job, I have helped you learn all the fundamental material in General Chemistry. I certainly hope that I'm giving you as good an education in General Chemistry as you would get at any other university, in fact, I would hope that I'm giving you a better Gen Chem education than you would get at most other universities. By occasionally using a standardized exam, I can see what things I'm doing well and what areas I need to improve to give future Gen Chem students the best possible education.
3. The format and length might vary slightly, but expect 70 questions and a 110 minute time limit. That's almost 2 hours, and 1.5 minutes per question. Some questions will be quicker than others, but at 1.5 minutes per question, none of them can be huge. Many of the questions on my exams are probably 10-20 minute questions by the time you work through all the parts, none of the questions on the ACS exam will be anywhere near that complex.
4. 70 questions means that each question is worth XX% of the total score. {I'll leave the calculation of "XX" for you to do as a practice math problem.} Scaling that to 200pts (the value of your final exam), means that each question would only be worth YYpts if I plugged your scores directly into my grade sheet. {Again, "YY" is a practice math problem...} On my exams, if you totally miss one of the big questions, you lose ~10%, sometimes more. Yikes.
5. It is quite unlikely that I will plug your scores directly into my grade sheet, I will almost certainly be using some sort of scaling formula to calculate a score out of 200 points. That doesn't mean you shouldn't prepare well for the exam, a good score can really help and a poor score can definitely hurt your final score/grade in the class.
6. There are resources available for you to use as practice. The actual ACS Gen Chem exams are not published, BUT every year the ACS prepares exams for the Chemistry Olympiad for high school students. These are not identical to the ACS Gen Chem exam, but the questions are similar and the style/format is almost the same. The ACS posts their old Chemistry Olympiad exams online, so you can look them over to help you prepare. Check out: http://portal.acs.org/portal/acs/corg/content?_nfpb=true&_pageLabel=PP_SUPERARTICLE&node_id=1508&use_sec=false&sec_url_var=region1&__uuid=1c147f5a-ee17-44e2-af0c-87ca446c65a8
for 10+ years of previous Chemistry Olympiad exams from both the local and national level competition.
Good luck in your preparation.
2012/04/18
Redox lab question
Quite a few people have questions about the redox lab, so let me give a hint/some guidance to everyone...
In the first part, you looked at reactivity and found Zn to be the most active metal, followed by Pb, then Cu. I'll just use those three as an example, you will also need to include Ni and Ag in your assignment. You measured the potential for a Zn/Pb cell, a Pb/Cu cell, and a Zn/Cu cell. Is there a relationship between those measured potentials? There's a relationship between those reactions, but how are cell potentials related to one another?
{Hmm, it looks like we could use the scientific method to analyze the data and results from this experiment. Who would have guessed?!}
On your hand-in assignment for lab, the "calculated" cell potentials for pairs that are not next to each other refers to the treatment you see above. You have measured all of the potentials for cell constructed from metals that are adjacent to each other in your activity series (step-wise potentials), so if there is a relationship between step-wise potentials and the potentials for cells constructed from metals that are not adjacent to each other in your activity series, you should be able to calculate the expected cell potential for those non-adjacent cells.
In the first part, you looked at reactivity and found Zn to be the most active metal, followed by Pb, then Cu. I'll just use those three as an example, you will also need to include Ni and Ag in your assignment. You measured the potential for a Zn/Pb cell, a Pb/Cu cell, and a Zn/Cu cell. Is there a relationship between those measured potentials? There's a relationship between those reactions, but how are cell potentials related to one another?
Zn(s) + Pb2+(aq) ⇄ Pb(s) + Zn2+(aq)
Pb(s) + Cu2+(aq) ⇄ Cu(s) + Pb2+(aq)
Zn(s) + Cu2+(aq) ⇄ Cu(s) + Zn2+(aq)
Are cell potentials like kinetics (the cell potential for the overall process is determined by the lowest potential)? Are cell potentials like equilibrium (the cell potential for the overall process is the product of the step-wise potentials)? Or is there another relationship between the step-wise potentials and the overall potential? When you think you see (observe) a relationship with the Zn/Pb/Cu system (hypothesis), check to see if the same relationship is true with some of the other cell combinations you measured.(test/experiment){Hmm, it looks like we could use the scientific method to analyze the data and results from this experiment. Who would have guessed?!}
On your hand-in assignment for lab, the "calculated" cell potentials for pairs that are not next to each other refers to the treatment you see above. You have measured all of the potentials for cell constructed from metals that are adjacent to each other in your activity series (step-wise potentials), so if there is a relationship between step-wise potentials and the potentials for cells constructed from metals that are not adjacent to each other in your activity series, you should be able to calculate the expected cell potential for those non-adjacent cells.
Labels:
cell potential,
chemistry,
lab,
redox,
scientific method,
voltaic cell
2012/04/12
Voltaic Cells
Not a lot of information right now, but I just finished drawing a voltaic cell diagram. Not perfect, but I'm pretty satisfied with it.
Labels:
chemistry,
oxidation,
redox,
reduction,
voltaic cell
2012/04/10
Balancing Redox Reactions
Balancing redox reactions can be pretty
simple for some system, but some redox reactions can be exceptionally
challenging. To balance any redox reaction, we can follow a
systematic set of steps, and every Gen Chem book happily provides a
set of steps. In my experience, most books use rules that require a
little bit of faith and function like a black-box. There are a LOT
of places that mistakes can be made when balancing redox reactions,
so I prefer to use rules that have built-in places to check my answer
before I go through the whole process. Here they are:
Balancing redox rules (in acidic
or neutral aqueous solutions):
1. Assign oxidation numbers to
all atoms in the equation
2. Identify the oxidation and
reduction half reaction
3. In each half reaction,
balance all atoms except hydrogen and oxygen
4. In each half reaction, add
electrons to the reactant or product side to balance the change in
oxidation state. Note: you are not adding
electrons to balance charge
5. In each half reaction, add
water molecules to balance any oxygen atoms
6. In each half reaction, add
H+(aq) to balance any hydrogen atoms
7. At this point, the half
reactions should be balanced, check the charge balance to confirm
8. Multiply each half reaction
by an appropriate integer to balance the electrons involved in the
oxidation and reduction processes
9. Add the half reactions
together
10. Again, the resulting
reaction should be balanced, check the charge balance to confirm
11. Cancel out any spectator
species, sit back and pat yourself on the back for writing such a
lovely balanced redox equation.
These rules work well, BUT rely upon
some assumptions. First, since we're using water and H+(aq),
the reaction must be taking place in aqueous solution that is neutral
or acidic. That's OK for most redox reactions in Gen Chem, but once
in a while we'll run into a rxn that takes place in basic
aqueous solution. How do we handle that? Think about it... basic
solutions have excess (relatively speaking) hydroxide ions.
Hydroxide ions react with H+(aq)
ions to form water. If a reaction is taking place in basic aqueous
solution, balance it according to the above rules and then add:
12. Add
enough OH-1(aq)
to each side to react with all the H+(aq)
that is present
13. Check
charge balance
14. Cancel
any excess water
As
with any process, practice is the key, so practice balancing redox
rxns, then practice a little more, and when you think you have it all
figured out, practice a couple more times. We'll do some of that in
class...
2012/04/06
Oxidation Numbers
Oxidation numbers describe the balance
between electrons and protons on an atom, whether that atom is
happily floating around all by itself or part of a massive molecule.
Oxidation numbers can be determined two different ways: by using
rules, or by looking at structure. Let's look at the rules first.
This is a very interesting molecule, it violates the octet rule and it has an unpaired electron. Looks like it would be pretty reactive. Looking at the electronegativities, oxygen is more electronegative than chlorine, so all of the bonding electrons will be assigned to oxygen, giving each oxygen 8 assigned electrons and the chlorine 3 assigned electrons.
Let's look at a redox reaction and assign Ox#s by the rules:Oxidation Numbers by the Rules:
1. For neutral, uncombined elements, Ox# = 0. Examples: Fe(s), H2(g), Hg(l), Ne(g)
2. For monoatomic ions, Ox# = charge. Examples: Fe2+(aq) {Ox# = +2}, P3-(g) {Ox# = -3}
3. Oxygen is almost always Ox# = -2, except in O2 {Ox# = 0, Rule #1} and peroxides {Ox# = -1}
4. Hydrogen is almost always Ox# = +1, except in H2 {Ox# = 0, Rule #1} and hydrides {Ox# = -1}
5. The sum of the Ox#s on all the atoms in a polyatomic molecule or ion is equal to the charge on the whole polyatomic molecule or ion.
Cl2(g) + 2
O2(g) ↔ 2
ClO2(g)
Cl2(g) : Rule
#1, Ox# = 0
O2(g) : Rule
#1, Ox# = 0
ClO2(g) : Rule
#3, oxygen is Ox# = -2.
ClO2(g) : Rule
#5, (Ox# Cl) + 2(Ox# O) = 0 (the charge on a neutral molecule)
(Ox# Cl) + 2(-2) = 0
(Ox# Cl) = +4
So in this redox reaction, each Cl is
going from 0 to +4, losing 4 electrons, Losing Electrons is
Oxidation; and each O is going from 0 to -2, gaining 2 electrons,
Gaining Electrons is Reduction.
For many substances, it's actually
easier to assign Ox#s by looking at the structure. The process is
very similar to finding Formal Charge, the electrons are just
assigned a little differently. Formal Charge assigns electrons as if
all bonds are purely covalent, meaning that all bonding pairs of
electrons are split with one electron given to each atom in the bond.
Oxidation Number assigns electrons as if all bonds are purely ionic,
meaning that all of the
bonding electrons go to the more electronegative element in the bond.
Again, let's look at an example, in fact, let's look at the same example as above, ClO2(g). Drawing a good Lewis Structure:Oxidation Number by the Structure:
1. Draw a good Lewis Structure
2. Assign all bonding electrons to the more electronegative element in the bond
3. Compare the electrons assigned to each atom to the valence electrons of the neutral element
This is a very interesting molecule, it violates the octet rule and it has an unpaired electron. Looks like it would be pretty reactive. Looking at the electronegativities, oxygen is more electronegative than chlorine, so all of the bonding electrons will be assigned to oxygen, giving each oxygen 8 assigned electrons and the chlorine 3 assigned electrons.
Neutral
oxygen has 6 valence electrons, we've assigned 8 electrons to oxygen,
so the oxidation number for oxygen in this molecule is -2, just like
we predicted using the rules. Neutral chlorine has 7 valence
electrons, we've assigned 3 electrons to chlorine, so the oxidation
number for chlorine in this molecule is +4, again, just like we
predicted using the rules. Both methods work. Why would you ever
use structures when the rules work? Try looking at hydrogen
peroxide, H-O-O-H, or a more complex molecule like glucose. The
rules don't always give the best picture of what's happening in a
molecule, and this can ultimately make it harder to predict
reactivity or other behaviors.
Labels:
chemistry,
lewis structure,
oxidation number,
redox
Redox - Definitions
If you want to understand chemistry,
you have to follow the electrons. If electrons are transferred
during a chemical reaction (as opposed to just being rearranged...),
then a reduction-oxidation process is taking place. To help keeping
track of the electron transfer in redox processes, we can use a
couple acronyms/mnemonics related to the definitions of reduction and
oxidation.
OIL / RIG - “Oxidation Is Losing
electrons” / “Reduction Is Gaining electrons”
LEO / GER - “Losing Electrons is
Oxidation” / “Gaining Electrons is Reduction”
Hmm, why is “reduction” associated
with gaining
electrons? Remember, electrons are negatively charged, so gaining
electrons increases the number of negatively charged particles
associated with an atom which reduces its net charge. But are we
really looking at “charge” to determine redox chemistry?
Sometimes it seems like it, but other times the charge doesn't seem
to line up with the processes. We really have to look at oxidation
number,
which is related to charge, but a with some subtle differences. One
way to distinguish charge and oxidation number is that “charge”
can be used to describe the net overall balance between electrons and
protons in a system that might contain multiple atoms, but “oxidation
number” describes the balance between electrons and protons for
each individual atom in a structure regardless of its size.
Oxidation numbers sound important enough for their own post, look for
it soon.
Another
thing that can cause some mix-ups is the term “oxidation” or {in
verb form} “oxidize”. {Or for the British English spellers in
the crowd, “oxidise”.} The element oxygen is very often involved
in redox reactions. Is oxygen usually undergoing oxidation or
reduction? You know you want to say oxidation, the words look so
similar... But if we start with molecular oxygen, O2(g),
it's almost always going to gain
electrons. Gaining Electrons is Reduction. GER, indeed!
The important thing to remember here is that reduction and oxidation
are ALWAYS coupled processes. You can't have one without the other.
This leads to some other terminology...
The process of one substance undergoing oxidation causes something else in the system to be reduced. The substance that is being oxidized is the reducing agent or reductant because it is causing reduction to take place.
The process of one substance undergoing reduction causes something else in the system to be oxidized. The substance that is being reduced is the oxidizing agent or oxidant because it is causing oxidation to take place.
So if oxygen is usually being reduced, it is a good oxidizing agent.
2012/04/04
Qualitative Analysis of Metal Cations - Week 2
This week in lab you're going to be analyzing an unknown mixture of the metal cations you studied last week. To do this, you need to look over the tests you did last week and find a way to sequentially use some or all of those tests to separate the cations. This is NOT a "run all the tests and figure it out later" experiment, you have to have a plan.
To develop your plan, assume you are starting with a mixture of all 5 cations, and you want to separate them into 5 different containers. The key to developing a good flow chart is the ability to separate solids from each other when multiple things precipitate. For example, if the first step of your flow chart is "add chromate", you will precipitate all 5 cations as their chromate salts. You have no way to separate these solids from each other, so this would be a VERY bad first step. Look over some of the multi-step tests you did last week. If adding some reagent causes 2 or 3 of the cations to form precipitate, and you have a way to separate those precipitates from each other (with another step in the multi-step test you performed last week), then that might be a good place to start.
As an example, what if you had a mixture of NaCl, NaNO3, sand, and sawdust. How could you separate them? If you added water, the NaCl and NaNO3 would dissolve, the sand would sink, and the sawdust would float. That accomplishes some of the separation, but what about the dissolved salts? If there was a reagent you could add to make chloride ions form a precipitate, like maybe Pb2+(aq), you would be able to separate the chloride from the nitrate.
{OK, picky people in the crowd, that doesn't exactly separate "NaCl" from "NaNO3", but it illustrates the point!}
Given the tests you performed, there are a few different flow charts that will work to separate the 5 cations you're working with, so if you have something that's a little different from someone else, that's OK. It would be great if you compared your flowchart to someone else's and had a discussion about the similarities and differences, it might lead you BOTH to make better flowcharts/plans.
To develop your plan, assume you are starting with a mixture of all 5 cations, and you want to separate them into 5 different containers. The key to developing a good flow chart is the ability to separate solids from each other when multiple things precipitate. For example, if the first step of your flow chart is "add chromate", you will precipitate all 5 cations as their chromate salts. You have no way to separate these solids from each other, so this would be a VERY bad first step. Look over some of the multi-step tests you did last week. If adding some reagent causes 2 or 3 of the cations to form precipitate, and you have a way to separate those precipitates from each other (with another step in the multi-step test you performed last week), then that might be a good place to start.
As an example, what if you had a mixture of NaCl, NaNO3, sand, and sawdust. How could you separate them? If you added water, the NaCl and NaNO3 would dissolve, the sand would sink, and the sawdust would float. That accomplishes some of the separation, but what about the dissolved salts? If there was a reagent you could add to make chloride ions form a precipitate, like maybe Pb2+(aq), you would be able to separate the chloride from the nitrate.
{OK, picky people in the crowd, that doesn't exactly separate "NaCl" from "NaNO3", but it illustrates the point!}
Given the tests you performed, there are a few different flow charts that will work to separate the 5 cations you're working with, so if you have something that's a little different from someone else, that's OK. It would be great if you compared your flowchart to someone else's and had a discussion about the similarities and differences, it might lead you BOTH to make better flowcharts/plans.
Labels:
cations,
chemistry,
flowchart,
lab,
qualitative
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